Question

Find
the area of triangle whose sides are 24cm, 32cm and 40cm​

Answer 1

Answer:

let the three sides of the triangle be a,b,c

a=24cm

b=32cm

c=40 cm

as the triangle is scalar (having three different sides), thus we have to calculate s

s=(a+b+c)/2

s=(24+32+40)/2

s=96/2=48

area of given triangle={s(s-a)(s-b)(s-c)} ^(1/2)

= square root of s(s-a)(s-b)(s-c)

= square root of 48(48-24)(48-32)(48-40)

= square root of 48*24*16*8

=square root of 18440

=135.79 cm sq

Step-by-step explanation:

Answer 2

Answer:

we can find area by heron's formula this is the formula used for when all sides are different

s=a+b+c/2. s means sum of all sides divided by 2

s=24+32+40/2

s=96/2

s=48

area of the triangle = √s(s-a)(s-b)(s-c)

√48(48-24)(48-32)(48-40)

√48(64)(16)(8)

(8)(4)√48(8)

32(4√3)(2√2)

627 units