Question

Find the area of triangle whose sides are 3cm ,4cm,5cm

Answer 1

Answer:

The area of the triangle is 6 centimeter square.

Step-by-step explanation:

Given : Triangle whose sides are 3cm ,4cm,5cm.

To find : The area of the triangle?

Solution :

Formula to find area of triangle is

$A= \sqrt{s(s - a)(s - b)(s - c)}$

Where, s is the semi perimeter,

$s=\frac{a+b+c}{2}$

a=3 ,b=4, c= 5 cm sides of the triangle

Substituting in the formula,

$s=\frac{3+4+5}{2}$

$s=\frac{12}{2}$

$s=6$

$A= \sqrt{s(s - a)(s - b)(s - c)}$

$A=\sqrt{6(6 - 3)(6 - 4)(6 - 5)}$

$A= \sqrt{6 \times 3 \times 2 \times 1}$

$A= \sqrt{36}$

$A= 6 cm^2$

Therefore, The area of the triangle is 6 centimeter square.

Answer 2

Given:

Sides of triangle = 3 cm, 4 cm, 5 cm

To Find: Area of triangle

Calculation:

• Area of triangle is given as $\sqrt{s(s-a)(s-b)(s-c)}$ where s is the semi-perimeter of triangle and a = 3 cm, b = 4 cm and c = 5 cm.

• Semi-perimeter, $s=\frac{a+b+c}{2} =\frac{3+4+5}{2} = 6$ cm

• Now, Area = $\sqrt{s(s-a)(s-b)(s-c)}$  = $\sqrt{6(6-3)(6-4)(6-5)} =\sqrt{6*3*2*1} =\sqrt{36} =6 cm^{2}$

Answer:

Area of the triangle is 6 $cm^{2}$.