Find the area of triangle whose sides are 42cm, 34cm and 20cm in length
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perimeter of the triangle= 34+42+20= 96 cm
semi perimeter= perimeter÷2= 96÷2=48 cm
area of triangle = √s* (s-a) (s-b) (s-c)
√48*(48-42)* (48-34)*(48-20)
√48*6*14*28
√112896
=336 cm square.unit
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Yes she is correct
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