Question

find the area of triangle whose sides are 6cm 5cm and 9cm​

Answer 1

Step-by-step explanation:

we can find area by heron's formula

where s is equal to 6+5+9/2=20/2=10

now by using heron's formula

s-a=10-6=4

s-b=10-5=5

s-c=10-9=1

so root of s(s-a)(s-b)(s-c)

root of 10x4x1x5

root of 200

=10root2

Answer 2

${\underline{\underline{\large{\textsf{\textbf{\pink{Question : }}}}}}}$

Find the area of triangle whose sides are 6cm, 5cm and 9cm.

${\underline{\underline{\large{\textsf{\textbf{\pink{Solution : }}}}}}}$

Given:

a= 6cm

b= 5cm

c= 9cm

To find:

Area of triangle=?

⠀⠀⠀⠀⠀_______________________

${\underline{\boldsymbol{\green{According~ to~ the~ question:}}}}$

By using Heron's formula

⠀⠀⠀⠀⠀$\sf{s = \dfrac{a + b + c}{2}}$

⠀⠀⠀⠀⠀$\sf{s= \dfrac{6 + 5 + 9}{2}}$

⠀⠀⠀⠀⠀$\sf{s = \dfrac{20}{2}}$

⠀⠀⠀⠀⠀${ \boxed { \sf{ s = 10cm}}}$

⠀⠀⠀⠀⠀$\sf{Area \: of \: triangle = \sqrt[] {s(s - a)(s - b)(s - c)} }$

⠀⠀⠀⠀⠀$\sf{Area \: of \: triangle} = \sqrt{10(10 - 6)(10 - 5)(10 - 9)}$

⠀$\sf{Area \: of \: triangle} = \sqrt{4 \times 5 \times 1}$

⠀⠀⠀⠀$\sf{Area \ of \ triangle } = \sqrt{20}$

⠀⠀⠀⠀⠀⠀$\sf{Area \ of \ triangle } = 2\sqrt{5}$

${\underline{\textsf{\textbf{Hence,the \ Area \ of \ Triangle \ is}}}}$2√5.