find the area of triangle whose sides are 9cm & 5cm &perimeter=21cm.
guyss the area should be found by herons formula ..plzz answers its important...I tried the answer is coming 0.6cm² . plzzz answer fast...explain properly
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Perimeter = A + B + C
21 = 9 + 5 + C
C = 7 cm
S = Perimeter/2
S = 21/2
S = 10.5 cm
Heron’s formula
Area = √(S(S-A)(S-B)(S-C))
Area = √(10.5(10.5 - 9)(10.5 - 5)(10.5 - 7))
Area = √303.1875
Area = 17.4 cm²
21 = 9 + 5 + C
C = 7 cm
S = Perimeter/2
S = 21/2
S = 10.5 cm
Heron’s formula
Area = √(S(S-A)(S-B)(S-C))
Area = √(10.5(10.5 - 9)(10.5 - 5)(10.5 - 7))
Area = √303.1875
Area = 17.4 cm²
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