find the area of triangle whose sides are in the ratio 5 is to 1 is to 13 and it's perimeter is 60 cm
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2
Let ABC be a triangle
then
AB + BC + CA = 60
5x +12x +13x = 60
30x=60
x = 2
AB = 10
BC = 24
CA = 26
Area of triangle = 1/2 x AB x BC
= 0.5 x 10 x 24
= 120 sq.cm
then
AB + BC + CA = 60
5x +12x +13x = 60
30x=60
x = 2
AB = 10
BC = 24
CA = 26
Area of triangle = 1/2 x AB x BC
= 0.5 x 10 x 24
= 120 sq.cm
Answered by
0
sum of ratios = 5+1+13 =19
perimeter = 60 cm
Therefore,
1st side =(5/19)*60 = 15.789 = (approximately) 15.79 cm
2nd side =(1/19)*60 = 3.157 = (approximately) 3.16 cm
3rd side =(13/19)*60 = 41.052 = (approximately) 41.05 cm
perimeter = 60 cm
Therefore,
1st side =(5/19)*60 = 15.789 = (approximately) 15.79 cm
2nd side =(1/19)*60 = 3.157 = (approximately) 3.16 cm
3rd side =(13/19)*60 = 41.052 = (approximately) 41.05 cm
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The area is =(1/2)*2nd side*3rd side
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