Question

find the area of triangle whose three sides are 50cm ,120cm,80cm​

Answer 1

Answer:

the area of the triangle = side+side +side

(50 +120 +80) cm = 250 cm^2

Answer 2

Given, three sides of a ∆ are 50,120 and 80cm

perimeter of ∆ = 50+120+80

= 250cm

half of perimeter = s = p/2 = 250/2 = 125cm

Using heron's formulae,

area of ∆ =

$\sqrt{s(s - a)(s - b)(s - c)}$

where a,b,c are the three sides if the ∆

a = 50

b = 120

c = 80

Now applying heron's formulae,

$\sqrt{125(125 - 50)(125 - 120)(125 - 80)} \\ </em><em>=</em><em>\sqrt{125(50)(5)(45)} \\ </em><em>=</em><em>\sqrt{5 \times 5 \times 5 \times 5 \times 2 \times 5 \times 5 \times 9 \times 5 } \\ </em><em>=</em><em>5 \times 5 \times 5 \times 3 \sqrt{2 \times 5} \\</em><em>=</em><em> 375 \sqrt{10}$

Area of the given ∆ = 375√10