Find the area of triangle whose two adjacent side are determined by the vector a vector=-2i^-5k^ and b vector=i^-2j^-k^
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it's (1/2)( a× b)
a×b = 4k -2j -5j -10i
= -10i -7j +4k
magnitude = √100 + 49 +16
So its( 1/2)( √164)
a×b = 4k -2j -5j -10i
= -10i -7j +4k
magnitude = √100 + 49 +16
So its( 1/2)( √164)
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