hey guys.......how do u solve this Q??
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Answered by
3
=> sinA(1 -2sin²A)/ cosA (2cos²A -1)
= > sinA/tanA ×1
=> tanA
hint → [ :- 1 -2sin²A = 1 - 2(1- cos²A) ]
[ = 2cos²A -1 ]
♣ hope it can help you ♣.....
= > sinA/tanA ×1
=> tanA
hint → [ :- 1 -2sin²A = 1 - 2(1- cos²A) ]
[ = 2cos²A -1 ]
♣ hope it can help you ♣.....
Answered by
5
sinA(1-2sin^2A)÷cosA(2cos^2A-1)
tanA(sin^2A+cos^2A-2sin^2A)÷(2cos^2A-sin^2A-cos^2A)
tanA proved
tanA(sin^2A+cos^2A-2sin^2A)÷(2cos^2A-sin^2A-cos^2A)
tanA proved
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