Question

find the area of triangle whose two of its sides are 8 cm and 11 cm and the perimeter is 32 CM

Answer 1

3rd side = perimeter-sum of anothor two sides
=32-19=13
now area = √(s-a)(s-b)(s-c) and s = 1/2 abc

Answer 2

Given perimeter 32 cm of ABC triangle.
let, AB = 8 cm and BC = 11 cm.

Therefore, AC = 32-8+11 = 32-19 = 13 cm.

Now, Semi-perimeter = (11+8+13)/2 = 16 cm.

Now area of triangle =
$\sqrt{16(16 - 11)(16 - 8)(16 - 13)}$

$\sqrt{16(5)(8)(3)}$

$\sqrt{1920} \: cm^{2}$