Question

find the area of triangle whose two sides are 8cm and 11 and it's semi perimeter is 16

Answer 1

Answer:

Semi perimeter = 16 cm

Perimeter = 2 x Semi perimeter = 2 x 16 = 32 cm

Let the unknown side be y cm.

8 + 11 + y = 32

19 + y = 32

y = 32-19 = 13 cm

Area =$\sqrt{16(16-8)(16-11)(16-13)}$

area=$\sqrt{16*8*5*3}$

area=$\sqrt{1920}$

area=$8\sqrt{30}$