Question

find the area of triangle whose vertices are (3,4),(-4,3) and (8,6)

Answer 1

Answer:

Area of triangle = 9/2 sq. units

Step-by-step explanation:

Vertices A(x₁,y₁) =(3,4),

              B(x₂, y₂) = (-4, 3)

              C(x₃, y₃) = (8, 6)

Area of triangle = 1/2 [x₁(y₂-y₃) +x₂(y₃-y₁) +x₃(y₁-y₂)]

                          = 1/2 [3(3-6) -4(6-4) + 8(4-3)]

                          = 1/2[ -9 -8 + 8]

                          = -9/2

                          = 9/2 Sq. units

Since area cannot be negative Area = 9/2 sq. units