Question

find the area of triangle whose vertices are (3,8), (-4,2), (5,-1).

Answer 1

HERE IS YOUR ANSWER

Answer 2

The area of the triangle is 37.5 square unit.

Step-by-step explanation:

Given : Triangle whose vertices are (3,8), (-4,2), (5,-1).

To find : The area of the triangle ?

Solution :

The area of the triangle is

$A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

Here, $(x_1,y_1)=(3,8), (x_2,y_2)=(-4,2), (x_3,y_3)=(5,-1)$

Substitute the value,

$A=\frac{1}{2}[3(2-(-1))+(-4)(-1-8)+5(8-2)]$

$A=\frac{1}{2}[3(3)+(-4)(-9)+5(6)]$

$A=\frac{1}{2}[9+36+30]$

$A=\frac{1}{2}[75]$

$A=37.5$

Therefore, the area of the triangle is 37.5 square unit.

#Learn more

If the vertices of the triangle are collinear.Find the area of that triangle​

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