Question

find the area of triangle whose vertices are A(-3,0), B(5,0) and (0,4)​

Answer 1

Given,

The coordinates of the three vertices of the triangle are = A(-3,0) , B(5,0) and C(0,4)

To find,

The area of the triangle ABC

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

The vertices of the traingle are -

A = (-3,0) = X1,Y1

B = (5,0) = X2,Y2

C = (0,4) = X3,Y3

Area of ∆ABC = ½ × [X1(Y2-Y3) + X2(Y3-Y1) + X3(Y1-Y2)]

= ½ × [-3(0-4) + 5 (4-0) + 0 (0-0)] (By putting values)

= ½ × (12+20+0)

= ½ × 32

= 16 sq. units

Hence, the area of ∆ABC is 16 sq. units.