Question

find the area of triangle whose vertices are as follows (bc,b+c) (ca,c+a) (ab,a+b)​

Answer 1

Answer:

Area of triangle =

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

Given,

(a,a+c),(a,c),(−a,c−a)

Area of triangle =

2

1

[a(c−c+a))+a(c−a−a−c)+(−a)(a+c−c)]

=

2

1

[a(a)+a(−2a)−a(a)]

=∣−a

2

∣=a

2

sq.units