Question

find the area of triangle with a vertices are (-5, -4), (-3, 2), (7, -6)​

Answer 1

Answer:

38 square units

Step-by-step explanation:

Let the given points be A= (-5,-4)

B= (-3,2)

C= (7,-6)

We know that,

Area of triangle

(∆) = 1/2 |x1(y2-y3) + x2(y3-y1) + x3(y1-y2) |

∆ = 1/2 |[-5(2-(-6)]+(-3) (-6-(-4)) + 7(-4-2) |

∆ = 1/2 | -5(8) + (-3) (-2) + 7(-6) |

∆ = 1/2 | -40 + 6 - 42 |

∆ = 1/2 |-76|

∆ = 76/2

∆ = 38 square units

Therefore Area of the triangle with given points is 38 square units