find the area of triangle with vertices (0,0), (4,0) and (0,5)
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9
Area of triangle with three vertices (0)+(5)(4)+(0)-(0)-(0)-(0)=20square units
Aasthachachan:
(0,0)is x1, y1
There is one more method but say I didn't remember
the question is of one mark
ohk that gr8
its wriiten here of 1 mark
Answered by
16
x1=0,x2=4,x3=0
y1=0,y2=0,y3=5
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
0(0-5)+4(5-0)+0(0-0)
so answer is 20
y1=0,y2=0,y3=5
x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
0(0-5)+4(5-0)+0(0-0)
so answer is 20
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