Question

Find the area of triangles whose vertices are as follows (Q. 1 to 4) : 1. (4,4), (3, 2) and (-3,16)​

Answer 1

Answer:

Plot the points in a rough diagram and take them in order.

Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B(−3,4) and C(−5,−6)Now the area of △ABC is

Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B(−3,4) and C(−5,−6)Now the area of △ABC is=21{(x1y2+x2y3+x3y1)−(x2y1+x3y2+x1y3)}

Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B(−3,4) and C(−5,−6)Now the area of △ABC is=21{(x1y2+x2y3+x3y1)−(x2y1+x3y2+x1y3)}=21{(4+18−10)−(−6−20−6)}

Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B(−3,4) and C(−5,−6)Now the area of △ABC is=21{(x1y2+x2y3+x3y1)−(x2y1+x3y2+x1y3)}=21{(4+18−10)−(−6−20−6)}=21(12+32)=22 sq.units.

Step-by-step explanation:

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