Find the area of whose dangerous of length 10 centimetre and 8.2 CM
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Answer:
diagonal = area = diagonal \timesdiagonal=area=diagonal×
length \div 2length÷2
= 10 \: cm \: \times \: 8.2 \: cm \: \div \: 2=10cm×8.2cm÷2
82 \: {cm}^{2} \: \div \: 282cm
2
÷2
= 41 \: {cm}^{2}.=41cm
2
.
Explanation:
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