Question

Find the area, perimeter and diagonal of a rectangle whose dimension are 8cm and 6cm respectively

Answer 1

I hope my helping hands will help you my friend.

Answer 2

Given ,

Length of the rectangle = 8cm

Breadth of the rectangle = 6cm

To find area of the rectangle =>

Area of the rectangle = l × b

= 8cm × 6cm

$= {48cm}^{2}$

$\boxed{Therefore \: area \: of \: the \: rectangle \: = \: {48cm}^{2}}$

To find perimeter of the rectangle =>

Perimeter of the rectangle = 2(l+b)

= 2(8+6)

= 2(14)

= 28cm

$\boxed{Therefore \: perimeter \: of \: the \: rectangle \: = \: 28cm}$

To find diagonal of the rectangle =>

$We \: know \: that \: {a}^{2} \: + \: {b}^{2} = \: {c}^{2} (Pythagorean \: Theorem )$

${a}^{2} + {b}^{2} = {c}^{2}$

$a = 8 \: and \: b = 6$

[substitute the values ]

${8}^{2} + {6}^{2} = {c}^{2}$

$64 + 36 = {c}^{2}$

$100 = {c}^{2}$

${c}^{2} = 100$

$c = \sqrt{100}$

$c = \sqrt{ ({10}^{2} })$

[square and root gets cancelled]

$c \: = \: 10$

$\boxed{Therefore \: diagonal \: of \: the \: rectangle \: = \: 10cm}$