Question

find the area pf rhombus where each side measures 20 cm and one of its diagonal is 32cm​

Answer 1

Answer:

Step-by-step explanation:

$\sqrt{20^2-16^2}\\\sqrt{400-256}\\=\sqrt{144}\\=12$

other diagonal =2*12 = 24

so area = 1/2*24*32 = 12*32 = 384