Question

find the area....

pls help....✌​

Answer 1

plese upload a clear picture bro i cant read the measurements

Answer 2

For surface I:

It is an isosceles triangle whose sides are a = 5 cm, b = 5 cm, c = 1 cm

= (0.75 x 3.3) cm2

= 2.475 cm2 (approx.)

For surface II:

It is a rectangle with length 6.5 cm and breadth 1 cm.

∴ Area of surface II = Length x Breadth

= (6.5 x 1) cm2 = 6.5 cm2

For surface III:

It is a trapezium whose parallel sides are 1 cm and 2 cm as shown in the figure given below:

For surface IV and V:

Surface V is a right-angled triangle with base 6cm arid height 1.5 cm.

Also, area of surface IV = area of surface V

= [latex]\frac { 1 }{ 2 }[/latex] x base x height

= ([latex]\frac { 1 }{ 2 }[/latex] x 6 x 15) cm2 = 4.5 cm2

Thus, the total area of the paper used = (area of surface I) + (area of surface II) + (area of surface III) + (area of surface IV) + (area of surface V) = [2.475 + 6.5 + 1.3 + 4.5 + 4.5] cm2

= 19.275 cm2

= 19.3 cm2 (approx.)