Question

find the area विद सॉल्यूशन ​

Answer 1

the solution is attached

hope you find it helpful

Answer 2

Answer:

let the vertex between 10cm and 12cm be A

and vertex between 10cm and 12 cm be B

let right angle at 18 cm line be C

let right angle at 12 cm be D

Step-by-step explanation:

draw a line parallel and perpendicular to CD, let the point where the line intersect BC be E .

in line BC, BE = BC - CE (CE= 12 cm)

BE=18-12=6 cm

Now we have 2 shapes , triangle ABE and Rectangle AECD

in triangle ABE

1st side = 10cm

2nd side=6cm

3rd side= ?? (we will find 3rd side using pythagoram theorem)

(Hyp)/\2=(base)/\2 +(perp)/\2

(10)/\2 = (6)/\2 + (perp)/\2

100 = 36 + (perp)/\2

(perp)/\2= 100 - 36

(perp)/\2= 64

perp= $\sqrt{64}$= 8

area of triangle= 1/2 x( base x perp)

1/2 x (6 x 8)

1/2 x 48=24 $cm^{2}$

area of rectangle AECD= length x breadth

12 x 8 =96 $cm^{2}$

Area of figure = area of triangle + area of rectangle

= 24 + 96 = 120$cm^{2}$

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