Question

find the area whose side are a=5cm,b=5cm and c =8cm

Answer 1

The area of the triangle is $12 cm^2$

By using they Pythagorean theorem, we can find the height of the triangle.

The hypotenuse of the triangle is 5 and a side if 4. Through the Pythagorean theorem, we can solve for the other side.

$b=\sqrt{c^2-a^2}$

Now we can substitute in the values to solve this.

$\sqrt{5^2-4^2} = b$

This simplifies to $\sqrt{9} = b$

so b = 3

The formula for the area of a triangle is $\frac{Base*Height}{x}$

So now we can input our know values for this formula

$\frac{8*3}{2}$

this simplifies down to $12 cm^2$

Answer 2

❤❤Here is your answer ✌ ✌

$\huge {\red {\bold {Answer}}}$

in triangle ADB:-

area of triangle=1/2×b×h.
area of triangle
=1/2×4×3=6cm square.

in triangle ADC:-

area of triangle=1/2×b×h.
area of triangle
=1/2×4×3=6cm square.

Total area of triangle =6 cm square +6cm square
=12 cm square✔