find the areas of the following polygons-
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preet2002:
pls answer
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Answered by
16
1) Area of AED+Area of bcde
(1/2*6*8)+ [1/2*(6+12)*(13-8)]
24 + (1/2*18*5)
24+45
69
3)(6*11)+[(25-11)*6]+[1/2*[(25-11)+10]*19.5-(6+5.5)]+(5.5*10)
66+(14*6)+(1/2*24*8)+55
121+84+96
301
(1/2*6*8)+ [1/2*(6+12)*(13-8)]
24 + (1/2*18*5)
24+45
69
3)(6*11)+[(25-11)*6]+[1/2*[(25-11)+10]*19.5-(6+5.5)]+(5.5*10)
66+(14*6)+(1/2*24*8)+55
121+84+96
301
Answered by
10
4) right side = 2+1 = 3 cm
left side = 3 cam
up side = 6cm
down = 5 + 1 = 6cm
Now its a rectangle
area of rectangle = l × b
= 6 ×3
= 18 cm²
now area of triangle =1/2 × b×h
= 1/2 ×1×1
= 0.5 cm²
area of polygon = area of rectangle - area of triangle
=18 - .5
= 17.5 cm²
left side = 3 cam
up side = 6cm
down = 5 + 1 = 6cm
Now its a rectangle
area of rectangle = l × b
= 6 ×3
= 18 cm²
now area of triangle =1/2 × b×h
= 1/2 ×1×1
= 0.5 cm²
area of polygon = area of rectangle - area of triangle
=18 - .5
= 17.5 cm²
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