find the areas of the triangle whose vertices are (2, 3)( - 1, 0 )(2, - 4)
Answers
Answered by
13
we know area of triangle is 1/2 | x1(y2-y3)+x2(y3-y1)+x3(y1-y2) |
=1/2 |2(0+4)-1(-4-3)+2(3+1) |
=1/2 |2(4)-1(-7)+2(4) |
=1/2 |8+7+8|
=1/2 |23|
=23/2
ANSWER IF WRONG
=1/2 |2(0+4)-1(-4-3)+2(3+1) |
=1/2 |2(4)-1(-7)+2(4) |
=1/2 |8+7+8|
=1/2 |23|
=23/2
ANSWER IF WRONG
Answered by
3
Area of triangle= 1/2(2*3+(-1)*-7+2*-3)
6+7+(-6)= 7
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