Question

Find the argument of i3​

Answer 1

Answer:

1+iv3 is the answer

Step-by-step explanation:

Answer 2

Answer:

-π/2

Step-by-step explanation:

z=i³

z=0+i³

z=0-i = (0, -1)

alpha = tan^-1 | Im(z)/Re(z) |

alpha = tan^-1 | -1/0 |

aplha = tan^-1 |0|

alpha = π/2

Therefore, we know that (0, -1) is in 4th quadrant.

So, according to formula,

theta = -alpha

theta = -π/2

∴ arg(z) = -π/2

Hope it helps