find the arithmetic mean of an ap with 17 terms whose ninthth term is 11
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Sum of N Terms of AP: S = n/2[2a + (n − 1) × d]
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Answer:
17th term of the A.P. is a
17 =a+(n−1)d
Given series is 5,8,11,14,....
Here a=5,d=3,a
17 =?
Therefore, a 17
=5+(17−1)3
⇒a 17
=5+16×3
⇒a 17 =53
Step-by-step explanation:
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