Question

Find the arithmetic mean of the following measurements: 3.88, 4.09, 3.92.
3.97, 4.02, 3.95, 4.03, 3.92, 3.98 and 4.06 .​

Answer 1

Answer:

3.982

Step-by-step explanation:

mean = sum of all observations / number of observations

mean of the following measurements: 3.88, 4.09, 3.92.

3.97, 4.02, 3.95, 4.03, 3.92, 3.98 and 4.06 .

= (3.88+4.09+3.92+ 3.97 + 4.02 + 3.95 + 4.03 + 3.92 + 3.98 + 4.06)/10

=39.82/10

= 3.982

so arithmetic mean of the following measurements: 3.88, 4.09, 3.92.3.97, 4.02, 3.95, 4.03, 3.92, 3.98 and 4.06 .= 3.982

Answer 2

Given Series :

3.88, 4.09, 3.92, 3.97, 4.02, 3.95, 4.03, 3.92, 3.98 , 4.06

To Find :

Arithmetic Mean

Solution :

Arithmetic Mean = $\bf \frac{Sum \: of \: Observations}{Total \: No.of \: Observations}$

$\sf \to \: Sum \: of \: Observations \: = 3.88 + 4.09 + 3.92 + 3.97 + 4.02 \\ \sf \: + 3.95 + 4.03 + 3.92 + 3.98 + 4.06$

$\sf\to \: 19.88 + 19.94$

$\bf\to \: 39.82$

$\sf \: Sum \: of \: Observations \: = 39.82$

$\sf \: Total \: No.of \: Observations \: = 10$

$\sf \to \: Mean \: = \frac{39.82}{10}$

$\bf \to Mean \: = 3.982$

$\sf \to \: 3.982 = 4$

$\therefore \sf \: Arithmetic \: Mean \: = 3.982 \: (4)$

More :

$\sf\bullet \: Mean \: = \frac{Sum \: of \: Observations }{Total \: No.of \:Observations }$

$\sf\bullet \: Median \: = Middle \: one$

$\sf\bullet \: Mode \: = Most \: repeated \: ones$