Find the arithmetic progression if it is known that a 1 +a 3 +a 5 =-12 a 1 a 2 a 3 =80
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Given a1+a5+a10+a15+a20+a24=225⇒a+a+4d+a+9d+a+14d+a+19d+a+19d+a+23d=225⇒6a+69d=225
⇒2a+23d=75 (where a is the first term & d is the common difference of AP)
S24=2n[2a+(n−1)d]
=224[2a+(23)d]=12×(2a+23d)=12×75=900
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