Question

Find the arithmetic Progression of 6 terms if first term is 2/3 and the last is 22/3

Answer 1

Sn = n/2 [ a+ l]

Sn = 6/2 [ ⅔ + 22/3 ]

Sn = 3 [ 8]

Sn = 24

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hope it will help you ....✌✌

Answer 2

Answer:

The required A.P. is :-

2/3, 2, 10/3, 14/3, 6, 22/3

Step-by-step explanation:

Given: 1st term a = 2/3

last (6th) term = 22/3

So, 6th term = 22/3

or, a + (6 - 1) d = 22/3

or, a + 5d = 22/3

or, 2/3 + 5d = 22/3

or, 5d = 22/3 - 2/3

or, 5d = 20/3

or, d =20/3 ÷ 5

or, d = 4/3

Therefore, 1st term = a + (n-1) d

= a + (1-1)d

= 2/3

2nd term = 2/3 + (2 - 1) × (4/3)

= 6/3

= 2

3rd term = 2/3 + (3-1) × (4/3)

= 10/3

4th term = 2/3 + (4-1) × (4/3)

= 14/3

5th term = 2/3 + (5-1) × (4/3)

= 18/3

= 6

6th term = 2/3 + (6-1) × (4/3)

= 22/3

Hence, the required A.P. is :-

2/3, 2, 10/3, 14/3, 6, 22/3

Hope this will help you.