Question

Find the arithmetic progression whose third term is 16 and the 7th term exceeds the 5th term by 12

Answer 1

Answer:

Step-by-step explanation:

Suppose a be the First term,

a3 = 16

a7 = a5 + 12  ............ (Eqn 1)

a7 ⇒ a5 + d + d = a5 + 2d ............(Eqn 2)

From Equation (Eqn 1) & (Eqn 2)

a5 + 12 = a5 + 2d 

2d = 12

d = 6

By the Information

a3 = 16

a3 = a + 2d = 16

Substitute the value of d

a + ( 2 × 6 ) = 16            

a + 12 = 16

a = 4

Hence, 

AP is 4, 10, 16, 22, 28.......

Answer 2

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