Math, asked by sk5433092, 7 months ago

Find the arla of on triangle whose
two equal sides are 12cm, 12 and
perimeter is 40 cm​

Answers

Answered by arhamjain9nov2007
0

Answer:

SOLUTION

Length of the equal sides = 12cm

Perimeter of the triangle = 30cm

Length of the third side = 30 - (12+12) cm = 6cm

Semi perimeter of the triangle(s) = 30/2 cm = 15cm

Using heron's formula,

Area of the triangle = √s (s-a) (s-b) (s-c)

                                      = √15(15 - 12) (15 - 12) (15 - 6)cm2

                                      = √15 × 3 × 3 × 9 cm2

                                      = 9√15 cm2

Step-by-step explanation:

Let The Third Side Be xcm.

Now Perimeter = 12+12+x

24+x = 30

x = 6

Now Find The Area Using Herons Formula

Semiperimeter = 30/2 = 15

Sq Root(15(15-12)(15-12)(15-6) ) = Sq Root(15*3*3*9) = Sq Root(1215) = 34.85 cm^2

So Area is 34.85cm^2.

PLZ MARK ME AS BRAINIST...........................,

AS IT TOOK A LOT OF TIME TO SOLVE THIS!!!!

Answered by IntelligentPPrince
0

 area \: of \: triangle = \frac{1}{2}  \times base \times height \\  =  \frac{1}{2}  \times 12 \times 40 \\  = 240 {cm}^{2}

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