find the asymptote for the equation
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xy(x+y)+a(y
2
+xy−x
2
)−10a
2
y=0
⇒(y−a)x
2
+(x+a)y
2
+ya(x−10a)=0
Assuming the asymptotes to be y=mx+c
Substituting
⇒(mx+c−a)x
2
+(x+a)(mx+c)
2
+(mx+c)a(x−10a)=0
For finding the coefficients putting the coefficients equal to zero
m+m
2
=0
m=−1,0
and (c−a)+2mc+am=0
For m=0
c=a
For m=−1
c−a−2c−a=0
c=−2a
For any vertical asymptotes dividing equation by m
2
⇒
m
2
x
2
(mx+c−a)+
m
2
(x+a)
(mx+c)
2
+
m
2
a
(mx+c)(x−10a)=0
m→∞
x+a=0
So asymptotes are
x+a=0
y−a=0
y+x+2a=0
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