Find the average of 6 numbers,if the sum of the first four is 40 and the sum of other two is 56.ans is 16 pls solve step by step
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Suppose the seven numbers are a, b, c, d, e, f, and g.
Average of first 4 number = 4
(a+b+c+d)/4 = 4
a+b+c+d = 16 ...................... (i)
Average of last 4 numbers = 4
(d+e+f+g)/4 = 4
d+e+f+g = 16 ...................... (ii)
The average of seven numbers = 3
(a+b+c+d+e+f+g)/7 = 3
a+b+c+d+e+f+g = 21 ............. (iii)
if we add (i) and (ii), the result is
a+b+c+d+d+e+f+g = 16+16
Lets put the value of seven numbers in the above expression
21 + d = 32
d = 11.
just change the digits
Average of first 4 number = 4
(a+b+c+d)/4 = 4
a+b+c+d = 16 ...................... (i)
Average of last 4 numbers = 4
(d+e+f+g)/4 = 4
d+e+f+g = 16 ...................... (ii)
The average of seven numbers = 3
(a+b+c+d+e+f+g)/7 = 3
a+b+c+d+e+f+g = 21 ............. (iii)
if we add (i) and (ii), the result is
a+b+c+d+d+e+f+g = 16+16
Lets put the value of seven numbers in the above expression
21 + d = 32
d = 11.
just change the digits
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