Question

Find the average of all the two digit number which are divisible by 8​

Answer 1

Step-by-step explanation:

8+16+24+32+.................+96

a = 8 , d=8 , n = 12

S(12) = 12/2 {2(8)+(12-1)8 }

= 6 { 16 + 88 }

= 6*104 = 624

average = 624/12 = 52

Answer 2

Two digit number divisible by 8 are

(16–24–32–40–48–56–64–72–80–88–96)

16,24,.........96

In this A.P

A=16,

D=8,

An​=96

An​=A+(n−1)D

96=16+(n−1)8

96=16+8n−8

8n=88

∴n=11

Hence, 11 number of two digit numbers are divisible by 8.

Now we have to find out the average of all the two digit number which are divisible by 8​:-

Average =(sum of given numbers ) ÷ ( number of given numbers )

               = ( 16+24+32+40+48+56+64+72+80+88+96) ÷ 11

               = 616 ÷11= 56

∴ 56 is the average of all the two digit number which are divisible by 8​.

Ans :-  56 is the average of all the two digit number which are divisible by 8​.

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