Find the average of first 40 natural numbers
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Answered by
3
sum of first n numbers= n (n+1)÷2. =40 (40+1)÷2 =40×41÷2= 820. Average =820÷40 =20.5
gayithri:
Hey guys! Thanks for solving it:D
Answered by
6
Hey!
Follow the simple formula given.
Sum of first "n" terms = n(n + 1)/2
So, sum of first 40 natural numbers = 40 (40 + 1)/2 = (40 x 41)/2 = 1640/2 = 820
Now, Average = Sum/ total number of terms
= 820/40 = 20.5
Hence, your answer is 20.5
Hope This Helps..
Follow the simple formula given.
Sum of first "n" terms = n(n + 1)/2
So, sum of first 40 natural numbers = 40 (40 + 1)/2 = (40 x 41)/2 = 1640/2 = 820
Now, Average = Sum/ total number of terms
= 820/40 = 20.5
Hence, your answer is 20.5
Hope This Helps..
Hey thank you for solving it!!! :D
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