Question

Find the average of first 40 natural numbers

Answer 1

sum of first n numbers= n (n+1)÷2. =40 (40+1)÷2 =40×41÷2= 820. Average =820÷40 =20.5

Answer 2

Hey!

Follow the simple formula given.

Sum of first "n" terms = n(n + 1)/2

So, sum of first 40 natural numbers = 40 (40 + 1)/2 = (40 x 41)/2 = 1640/2 = 820

Now, Average = Sum/ total number of terms
= 820/40 = 20.5

Hence, your answer is 20.5

Hope This Helps..