Question

find the average of the first 97 natural numbers

Answer 1

Hi,

Average of first n natural numbers = n(n+1)/2

According to the problem given ,

n = 97,

_______________________________________________

Average =( sum of the observations)/ number of observations )

_______________________________________________

Sum of first 97 natural numbers = [ 97 ( 97 + 1 ) ] / 2

= [ 97 × 98 ] /2

= 97 × 49

= 4753 -----( 1 )

Average of first 97 natural numbers = ( 1 ) / 97

= 4753 / 97

= 49

Therefore,

Average of the first 97 natural numbers = 49

I hope this helps you.

:)

Answer 2

Answer:

49

Step-by-step explanation:

As we know that, the sum of first n natural nos. is

n(n+1) /2.

Here, n=97 ,

Therefore, 97(98) /2 but we need to calculate the average of first 97 nos.

so, 97(98) /(2*97) =49