Find the Average of the Least and Second Least MarkThe marks scored by 40 students in a test are distinct and have integral values. If the highest score is 120 and their average score is 100.5, then find the average of the least and the second least mark.
Answers
Answered by
22
The total scored by all 40 students in the exam = 100.5 * 40 =4020
Let us assume that the students scored marks: 81, 82, 83, 84, 85,....100, 101, 102, .... ,118, 119, 120.
The total = (81+120)/2 * 40 = 4,020.
Average = 101.5.
If any student scores less than 81, then average will be less than 101.5. The total will be less than 4,020. Thus the students scored the highest possible distinct scores from 81 to 120.
Answer: average of least and second least: (81 + 82)/2 = 81.5
Let us assume that the students scored marks: 81, 82, 83, 84, 85,....100, 101, 102, .... ,118, 119, 120.
The total = (81+120)/2 * 40 = 4,020.
Average = 101.5.
If any student scores less than 81, then average will be less than 101.5. The total will be less than 4,020. Thus the students scored the highest possible distinct scores from 81 to 120.
Answer: average of least and second least: (81 + 82)/2 = 81.5
kvnmurty:
clik on thanks.. select best ans..
Similar questions