find the base of a triangle whose area is 0.48 DM square and altitude is 8 cm
Answers
Answered by
58
1 dm=10 cm
therefore, 1dm^2=100cm^2
so,
0.48*100cm^2
=48cm^2
therefore,
1/2×8×base=48
=>base=12 cm!!!
hope this helps
therefore, 1dm^2=100cm^2
so,
0.48*100cm^2
=48cm^2
therefore,
1/2×8×base=48
=>base=12 cm!!!
hope this helps
ParthThakre9965:
hope this helped
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Answered by
41
Area of triangle = 0.48 dm sq.
(1dm=10cm)
0.48dm sq. =10cm sq.
Area=10cm sq.
Altitude =8cm
Area of triangle =1/2*b*h
4.8cm=1/2*b*8
b= 48/4
b=12cm
(1dm=10cm)
0.48dm sq. =10cm sq.
Area=10cm sq.
Altitude =8cm
Area of triangle =1/2*b*h
4.8cm=1/2*b*8
b= 48/4
b=12cm
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