Question

Find the base of an isosceles triangle whose
area is 12 cm^2and one of the equal sides is
5 cm.

Answer 1

Answer:

A=b×h/2

12cm^2=b×h/2

24/5=b

4.5 cm =b

Answer 2

SOLUTION:-

LET THE BASE OF TRIANGLE BE X CM. WE HAVE,

AREA=12 CM^2 EQUAL SIDE = 5 CM

SINCE, AREA OF TRIANGLE= 1/2 * B*H

PUTTING THE KNOWN VALUES WE GET,

12=1/2*5*B

=> B= 12*2*1/5

=>B=4.8

HENCE, THE BASE IS 4.8 CM.

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