find the biggest and smallest angle of the figure
plz solve it with full formula
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Answers
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ANSWER
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Largest angle = \angle3∠3 = 130°
Smallest angle = \angle2∠2 = 20°
Explanation :
From the figure, the sum of all angles = 360°
\angle∠ 1 + \angle∠ 2 + \angle∠ 3 + \angle∠ 4 = 360°
(2x + 30) + (3x - 70) + (3x + 40) + (5x - 30) = 360°
13x - 30 = 360°
13x = 390°
x = 390/ 13
x = 30°
Hence, the angles are
(2x + 30) = 90°
(3x - 70) = 20°
(3x + 40) = 130°
(5x - 30) = 120°
Therefore, largest angle = \angle 3∠3 = 130°
Smallest angle = \angle 2∠2 = 20
Answer:
sum of all angles here = 360°
angle 1st + angle 2nd + angle 3rd + angle 4th= 360°
first angle= 2x + 30
second angle = 3x - 70
third angle = 3x + 40
fourth angle = 5x - 30
2x + 30 + 3x - 70 + 3x + 40 + 5x - 30 = 360°
2x + 3x + 3x + 5x + 30 + 40 - 70 - 30 = 360°
(2+3+3+5) X + (30+40-70-30) = 360°
(5+8) X + (70-100) = 360°
13x - 30 = 360°
13x = 360+30
13x = 390
x = 390/13
X = 30°
first angle = 2x + 30
= 2×30+30
= 60+30
= 90
second angle = 3x -70
= 3×30-70
= 90-70
= 20°
third angle = 3x + 40
= 3× 30+40
= 90+40
= 130°
fourth angle= 5x - 30
= 5×30-30
= 150-30
= 120°
therefore the smallest angle is 20° and the largest angle is 130°