Find the boiling point of a solution containing 0.520
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Answer:
ΔTb=Kb×m
=Kb×WBMB×1000WA
ΔTb=0.52×0.52180×100080.2
=270.414436=0.0187
∴ Boiling Point = 373 + 0.0187 = 373.0187
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