Question

Find the breadth of a rectangular plot of land, if its area is 440 m² and the length is 22 m. Also find its perimeter​

Answer 1

Step-by-step explanation:

Area =length×breadth

⇒22×(breadth)=440

breadth=20 cm

Perimeter =2(length×breadth)

2(20+22)=2×42=84 m

Answer 2

Question:

Find the breadth of a rectangular plot of land, if its area is 440 m² and the length is 22 m. Also find its perimeter.

To find:

• breadth of rectangular plot
• Perimeter of rectangular plot

Understanding concept:

Here concept of area of rectangle is used.As we know area is equal to length * breadth. By using this formula first we find value of breadth. It's also asked to find value of Perimeter for which we need value of length and breadth, where length is given and breadth we will find first .And then finally we can find Perimeter by using formula: p=2(l+b).

Given:

• Area of rectangular plot = 440 m²
• Length of rectangular plot = 22 m

Formula used:

• $\orange{\sf Breadth = \dfrac{Area}{length}}$
• $\orange {\sf \: Perimeter \: of \: rectangle = 2(length + breadth)}$

Answer:

We know:

Area of rectangle=Length ×Breadth

From this formula we can find breadth of rectangular plot

$\therefore \: \sf Breadth = \dfrac{Area}{length}$

$: \implies \: \sf Breadth = \dfrac{440}{22}$

$: \implies \: \sf Breadth = \dfrac{ { \cancel{440} \: }^{20} }{ {\cancel{22} \: }^{1} }$

$: \implies \pink{ \star \sf \boxed{ \: \sf \: Breadth = 20cm} \star}$

we know :

$\sf \: Perimeter = 2(length + breadth)$

By using this formula we can find perimeter of rectangular plot

$:\implies \sf \: Perimeter= 2(22 + 20)$

$:\implies \sf \: Perimeter= 2(42)$

$:\implies \blue{\star \boxed {\sf \: Perimeter = 84cm}\star}$

Additional Formulas:

• $\sf Area \: of \: triangle = \dfrac{1}{2} \times base×height$

• $\sf Perimeter \: of \: triangle =side \:1 + side \: 2 + side3$

• $\sf \: Area \: of \:square = {side}^{2}$

• $\sf Perimeter \: of \: square = 4 \times side \\ \sf or \\ \sf Perimeter \: of \: square =side \times side \times side \times side$

• $\sf Area \: of \: cirle = \pi \: {radius}^{2}$

• $\sf Perimeter \: of \: cirle = 2\pi \: radius$

• $\sf Area \: of \: cube = 6 \times {side}^{2}$

• $\sf \: volume \: of \: cube = {side}^{3}$

$\pink{\huge{\underline{ ———————————————————————————————————————————————————————}}}$

And all we are done! ✔

:D