Find the breadth of the rectangle whose perimeter is 360 cm and whose length is
(i) 116 cm
Answers
Answered by
3
Answer:
Perimeter of rectangle = 2(l+b)
Given length l = 116cm
Perimeter = 360cm
2(l+b) = 360
2(116+b) = 360
116+b = 2×180 /2
b=180−116
b=64
Similar questions