Question

Find the c.s.a of Cuboid of length breadth height 9cm 10cm 5cm reps.

Answer 1

given length is 9cm , breadth 10cm and height 5cm . formula for CSA of cuboid is 2(l+b)×h=2(9+10)×5=2×19×5=19×10=190cm^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{L.S.A\:of\:cuboid=190\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Length(l) = 9 \: cm} \\ \\ : \implies \text{Breadth(b) =10 \: cm} \\ \\ : \implies \text{Height(h) = 5 \: cm} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{L.S.A \: of \: cuboid = ? }$

• According to given question :

$\bold{As \: we \: know \: that} \\ : \implies \text{L.S.A \: of \: cuboid} = 2(l + b)\times h\\ \\ : \implies \text{L.S.A \: of \: cuboid} = 2(9 +10 ) \times 5\\ \\ : \implies \text{L.S.A \: of \: cuboid} = 2\times 19\times 5 \\ \\ : \implies \text{L.S.A \: of \: cuboid} = 38 \times 5 \\ \\ \green{: \implies \text{L.S.A \: of \: cuboid = 190 \:{cm}}^{2} } \\ \\ \purple {\text{some \: formula \: related \: to \: this \: topic}} \\ \pink {\circ \: \text{T.S.A\: of \: cuboid = }2(lb+bh + hl) } \\ \\ \pink {\circ \: \text{Volume \: of \: cuboid = }l \times b \times h}$