Question

find the canvas required to make a covered cubicle of edge 8m,in a park.

Answer 1

length of cube = 8m
total surface area = 6*l*l
                       = 6*8*8 m^2
                       = 384 m^2
the canvas required is 384 m^2

hope it helps you!!:))

Answer 2

Given;
Length(l) of the cubicle=8 m.

The canvas required= total surface area of cube

=6l²
=6 x 8 x 8 m²
=6 x 64 m²
=384 m².

Hope i helped u:)