Find the capacity in liters of a conical vessel having hight 8cm and slant height 10cm
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By Pythagoras Theorem,
r^2+h^2=l^2
r^2=l^2-h^2
=10^2-8^2
=100-64
=36
r=√36
=6 cm
1 m^3 = 1000 litres
100cm x 100cm x 100 cm=1000litres
Dividing both sides by 1000 x 1000, we get
1 cm^3= 1/1000 litres
=1 ml
1000ml= 1 litre
By Pythagoras Theorem,
r^2+h^2=l^2
r^2=l^2-h^2
=10^2-8^2
=100-64
=36
r=√36
=6 cm
1 m^3 = 1000 litres
100cm x 100cm x 100 cm=1000litres
Dividing both sides by 1000 x 1000, we get
1 cm^3= 1/1000 litres
=1 ml
1000ml= 1 litre
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