Question

find the capacity of a rectangular cistern whose length is 6 m and breadth 2.5 m and depth 1.4 m. also find the area of the iron sheet required to make the cistern.

plz give the answer with method

Answer 1

$\boxed{\boxed{\boxed{\bold{\red{Solution :\longrightarrow}}}}}$

$\boxed{\boxed{\boxed{\bold{\blue{Given,}}}}}$

$\bold{Lenght \: (L)= 6 \: m} \\ \\ \bold{Breadth \: (B) = 2.5 \: m }\\ \\ \bold{Height \: (H) = 1.4 \: m}$

$\bold\pink{Volume \: \: \: \: of \: \: \: \: the \: \: \: \: cistern}$

$\bold{= L \times B \times H}$

$\bold{ = (6 \times 2.5 \times 1.4) \: {m}^{3}} \\ \\ \bold{= 21 \: {m}^{3} }$
$\bold\purple{Capacity \: \: \: \: of \: \: \: \: the \: \: \: \: cistern}$

$\bold{= 21 \times 1000 \: \: litres} \\ \\ \bold{ = 210000 \: \: litres} \: \: \bold\green{\boxed{ Ans}}$

$\bold\green{Area \: \: \: of \: \: \: the \: \: \: iron \: \: \: sheet \: \: \: required} \\ \bold\green{to \: \: \: make \: \: \: the \: \: \: cistern = Total \: \: \: }\\ \bold\green{Surface \: \: \: Area \: \: of \: \: the \: \: \: cistern}$

$\bold{= 2(lb + bh + hl)} \\ \\ \bold{= 2(6 \times 2.5 + 2.5 \times 1.4 + 6 \times 1.4) \: \: {m}^{2} }\\ \\ \bold{= 2(15 + 3.5 + 8.4) \: \: {m}^{2}} \\ \\ = \bold{(2 \times 26.9) \: {m}^{2}} \\ \\ \bold{= 53.8 \: {m}^{2} }\: \: \bold\green{\boxed{ Ans}}$

$\boxed{\boxed{\boxed{\bold{I \: \: hope \: \: it \: \: will \: \: help \: \: you.}}}}$

Answer 2

Answer:

Capacity=(l×b×h)m³

Area of iron sheet=TSA of the cistern

=2(lb+bh+lh)m²