If the resistance is halved and the current is 0.3 and voltage is 6 , what will the current be? What is the new value of resistance?
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According to Ohm’s law V=IR
Hence when nothing changed Io=VRIo=VR
When potential difference is doubled and resistance is halved, then the current flowing is given by
I′=V′/R′
=2×V/R/2
=4V/R
=4 I o
Hence current will become 4 times the original value.
Hence when nothing changed Io=VRIo=VR
When potential difference is doubled and resistance is halved, then the current flowing is given by
I′=V′/R′
=2×V/R/2
=4V/R
=4 I o
Hence current will become 4 times the original value.
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